Question

How many moles of Fe₂O₃ are there in 0.54 liters of a 1.6 M solution?

Answer 1

Answer: 0.86 mol

This is a molarity problem, in which M is defined by:

$\frac{n(moles of solute)}{v(liters of solution)}$and the units are moles/liter

With this information in mind, we can plug in M and v already so that:

1.6 $\frac{mol}{L}$= $\frac{xmol}{0.54L}$ of Fe₂O₃

If we multiply 0.54 L from both sides, we will get:

0.864 mol = x mol of Fe₂O₃

Rounding that to sigfigs, we get that the number of moles within this Fe₂O₃ solution is 0.86 mol; therefore, that is the answer.

I hope this helped!