Respuesta :

Answer: 0.86 mol

This is a molarity problem, in which M is defined by:

[tex]\frac{n(moles of solute)}{v(liters of solution)}[/tex]and the units are moles/liter

With this information in mind, we can plug in M and v already so that:

1.6 [tex]\frac{mol}{L}[/tex]= [tex]\frac{xmol}{0.54L}[/tex] of Fe₂O₃

If we multiply 0.54 L from both sides, we will get:

0.864 mol = x mol of Fe₂O₃

Rounding that to sigfigs, we get that the number of moles within this Fe₂O₃ solution is 0.86 mol; therefore, that is the answer.

I hope this helped!

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