Answer:
let first equation be y=x^2-14x+23
second equation be y=-3x+5
now substitute the vale of y in equation second
y=-3x+5
x^2-14x+23=-3x+5
x^2-14x+3x=5-23
x^2-11x=-18
x^2-11x+18=0
x^2-(9+2)x+18=0
x^2-9x-2x+18=0
x(x-9)-2(x-9)=0
(x-2)(x-9)=0
either x-2=0 Or, x-9=0
x-2=0
x=0+2
x=2
x-9=0
x=0+9
x=9
therefore x=2,9
Step-by-step explanation:
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Answer:
(2, - 1 ) and (9, - 22 )
Step-by-step explanation:
Given the 2 equations
y = x² - 14x + 23 → (1)
y = - 3x + 5 → (2)
Substitute y = x² - 14x + 23 into (2)
x² - 14x + 23 = - 3x + 5 ( subtract - 3x + 5 from both sides )
x² - 11x + 18 = 0 ← in standard form
(x - 2)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 9 = 0 ⇒ x = 9
Substitute these values into (2) for corresponding values of y
x = 2 : y = - 3(2) + 5 = - 6 + 5 = - 1 ⇒ (2, - 1 )
x = 9 : y = - 3(9) + 5 = - 27 + 5 = - 22 ⇒ (9, - 22 )
