Question

Find one value of xxx that is a solution to the equation:
(2x+3)^2-6x-9=0(2x+3)
2
−6x−9=0left parenthesis, 2, x, plus, 3, right parenthesis, squared, minus, 6, x, minus, 9, equals, 0
x=x=x, equals

Answer 1

Answer:

-3/2

Step-by-step explanation:

Given the funtion

(2x+3)² - 6x+9 = 0

(2x+3)² = 6x + 9

Expand

4x²+12x+9 = 6x + 9

4x²+12x - 6x = 0

4x²+6x = 0

4x² = -6x

4x = -6

x = -6/4

x = -3/2

Hence the value of x is -3/2