Respuesta :

Answer:

The approximate area by Riemann Sum of the curve is represented by [tex]A = 0.4\cdot \Sigma\limits_{t = 1}^{n} [2\cdot (2+0.4\cdot t)^{3} - 4][/tex].

Step-by-step explanation:

The area below the curve is estimated by the concept of Riemann Sum with right endpoint rectangles, which is defined by the following formula:

[tex]A = \left(\frac{\Delta x}{n} \right) \cdot \Sigma \limits_{t = 1}^{n} g\left (x_{o} + \frac{\Delta x}{n}\cdot t \right)[/tex] (1)

Where:

[tex]A[/tex] - Area below the curve, in square units.

[tex]n[/tex] - Number of rectangles, no units.

[tex]x_{o}[/tex] - Lower bound of the interval, in units.

[tex]\Delta x[/tex] - Length of the interval, in units.

[tex]t[/tex] - Summation index.

If we know that [tex]g(x) = 2\cdot x^{3} - 4[/tex], [tex]n = 10[/tex], [tex]x_{o} = 2[/tex] and [tex]\Delta x = 4[/tex], then the area below the curve is represented by the following equation:

[tex]A = 0.4\cdot \Sigma\limits_{t = 1}^{n} [2\cdot (2+0.4\cdot t)^{3} - 4][/tex]

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