Question

Calculate the volume 3.00 moles of a gas will occupy at 24.0°C and 105.2
kPa,
140. L
35.4L
15.4L
70.4L

Answer 1

Answer:

70.34 litres

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information given in the question;

n = 3 moles

V = ?

P = 105.2 KPa = 105.2/101 = 1.04atm

T = 24.0°C = 24 + 273 = 297K

Using PV = nRT

1.04 × V = 3 × 0.0821 × 297

1.04V = 73.15

V = 73.15 ÷ 1.04

V = 70.34 litres.