Given:
The radius of smaller cylinder is 2 m.
The radius of larger cylinder is 8 m.
The height of smaller cylinder is 14 m.
Both cylinders are similar.
To find:
The height of larger cylinder.
Solution:
It is given that the both cylinders are similar to each other.
We know that the corresponding sides of similar figure are proportional.
Let height of the larger cylinder is [tex]h_2[/tex].
[tex]\dfrac{r_1}{r_2}=\dfrac{h_1}{h_2}[/tex]
[tex]\dfrac{2}{8}=\dfrac{14}{h_2}[/tex]
[tex]\dfrac{1}{4}=\dfrac{14}{h_2}[/tex]
On cross multiplication, we get
[tex]1\times h_2=14\times 4[/tex]
[tex]h_2=56[/tex]
Therefore, the height of the larger cylinder is 56 m.
