Answer:
using pythagoras theorem
H^2=P^2+B^2
h=5[tex]\sqrt{2}[/tex] and let P=4[tex]\sqrt{2}[/tex] and B=x
so,
(5[tex]\sqrt{2}[/tex])^2=(4[tex]\sqrt{2}[/tex])^2+[tex]x^{2}[/tex]
50=32+[tex]x^{2}[/tex]
50-32=[tex]x^{2}[/tex]
18=[tex]x^{2}[/tex]
[tex]\sqrt{18}[/tex]=x
3[tex]\sqrt{2}[/tex]=x
Step-by-step explanation:
