Question

According to Ohm's law, determine the
experimental current for these values in Table A.
voltage = 5 V, resistance = 20 N:
A
voltage = 20 V, resistance = 20 N:
A
voltage = 50 V, resistance = 20 N:
A

Answer 1

Solution :

We know, by to Ohm's law :

$Current = \dfrac{Voltage}{Resistance}$

For, case 1 :

$I = \dfrac{5}{20}\ A = 0.25 \ A$

For, case 2 :

$I = \dfrac{20}{20} \ A\\\\I = 1 \ A$

For, case 3 :

$I = \dfrac{50}{20}\ A\\\\I = 2.5 \ A$

Therefore, this is the required solution.