Answer:
A Exactly one solution
Step-by-step explanation:
[tex]\left \{ {{6x-3y=9} \atop {6x+y=9}} \right.\\\\\left \{ {{6x-3y=9} \atop {-6x-y=-9}} \right\\\\Then, \\\\-4y=0\\\\\\ y=0\\\\[/tex]
Putting y=0 at second equation, we have
[tex]-6x=-9\\\\x=\frac{9}{6} =\frac{3}{2}[/tex]
The unique solution is [tex](\frac{3}{2} , 0)[/tex]
