Answers:
- Problem 5) x = 4
- Problem 6) y = 8
- Problem 7) z = 4
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Explanations:
Problem 5)
Assuming HEFG is a parallelogram, this means the opposite sides are the same length.
EH = GF
x-3 = 4x-15
x-4x = -15+3
-3x = -12
x = -12/(-3)
x = 4
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Problem 6)
We'll use the same idea from problem 5. The opposite sides EF and HG are congruent
EF = HG
3y = 3x+12
3y = 3*4+12
3y = 24
y = 24/3
y = 8
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Problem 7)
For any parallelogram, the diagonals always cut each other in half.
Therefore HK = 2z+3 is exactly half that of segment HF = 22
Put another way, HF is twice as long as HK
2*(HK) = HF
2*(2z+3) = 22
4z+6 = 22
4z = 22-6
4z = 16
z = 16/4
z = 4
