Question

g a 144 g metal bar requires 2500 J to change its temperature from 23.5 to 100 degree C what is the specific heat of the metal

Answer 1

Answer:

226.9 J·kg⁻¹·°C⁻¹

Explanation:

The specific heat of a substance can be defined as the amount is heat that has to be added in order for a given mass of the substance to increase its temperature:

• c = ΔQ/(m*ΔT)

In this case:

• ΔQ = 2500 J

• m = 144 g ⇒ 144 g / 1000 = 0.144 kg

• ΔT = 100 - 23.5 = 76.5 °C

We input the data:

• c = 2500 J / (0.144 kg * 76.5 °C)

And calculate c:

• c = 226.9 J·kg⁻¹·°C⁻¹