Answer:
See explanation
Step-by-step explanation:
The question is incomplete; So, I will solve the question generally.
Assume the following;
[tex]l \to length[/tex]
[tex]w \to width[/tex]
[tex]h \to height[/tex]
Since the water level must be 2 inches below the tank height, the water height is:
[tex]H \to h - 2[/tex]
So, the water volume is:
[tex]Volume = l * w * H[/tex]
[tex]Volume = l * w * (h - 2)[/tex]
Hence, the expression is:
[tex]Volume = l * w * (h - 2)[/tex]
Assume that:
[tex]l = 5; w = 10; h = 8[/tex]
The volume becomes:
[tex]Volume = 5 * 10 * (8 - 2)[/tex]
[tex]Volume = 5 * 10 * 6[/tex]
[tex]Volume = 300[/tex] cubic units