24 boys, 45 girls and 281 adults are the members of a badminton club.
50 more children join the club.
The number of girls is now 18% of the total number of members.
How many of the 50 children were boys?

Respuesta :

24+45+281+50=400

(45+n/400)×100=18

45+n=18×4=72

n=72-45=27

50-27=23.

hope it's correct

23 of the 50 children added were boys. The answer is 23 boys

Given that 24 boys, 45 girls and 281 adults are the members of a badminton club.

Total number of people as members of badminton = 24 + 45 + 281 = 350

Percentage of girls = girls/total number x 100

% of girls = 45/350 x 100

% of girls = 12.9%

If 50 more children join the club, and the number of girls is now 18% of the total number of members. Then, the new total number of members will be

New total members = 350 + 50 = 400

Let g = new added girls from the children

Percentage of girls = girls/total number x 100

18 = (g + 45) / 400 x 100

18/100 =  (g + 45) / 400

cross multiply

0.18 x 400 = g + 45

72 = g + 45

make g the subject of formula

g = 72 - 45

g = 27 girls

To get the number of boys added, take 27 away from the 50 children. That is,

The number of boys added = 50 - 27 = 23 boys

Therefore, 23 of the 50 children added were boys

Learn more about arithmetic here: https://brainly.com/question/6561461

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