Respuesta :

the answer is

y≥2x/5+2

Step-by-step explanation:

we moved the y to the right site and the -10 to the left site

so we had

2x+10≤5y

and then we devided by 5

2x/5+10/5≤y

y≥2x/5+2

hopefully its correct

Answer:  Choice D

[tex]y \ge \frac{2}{5}x +2\\\\[/tex]

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Work Shown:

[tex]2x - 5y \le -10\\\\-5y \le -2x-10\\\\y \ge \frac{-2x-10}{-5} \ \text{ ... see note1 below}\\\\y \ge \frac{-2x}{-5} - \frac{10}{-5}\\\\y \ge \frac{2}{5}x +2 \ \text{ ... answer is choice D}\\\\[/tex]

Note1: when dividing both sides by a negative number, the inequality sign flips.

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Here's another approach that doesn't involve dividing both sides by a negative number.

[tex]2x - 5y \le -10\\\\2x \le -10+5y\\\\2x +10\le 5y\\\\5y \ge 2x+10 \ \text{ .... see note2 below}\\\\y \ge \frac{2x+10}{5}\\\\y \ge \frac{2x}{5} + \frac{10}{5}\\\\y \ge \frac{2}{5}x +2\\\\[/tex]

Note2: I swapped the left and right sides. Doing this swap means that the inequality sign must flip as well.

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