Respuesta :

Given:

A prism with height 5 cm and equilateral triangular base with side 2 cm.

To find:

The total surface area of the prism.

Solution:

Area of an equilateral triangle is:

[tex]A_1=\dfrac{\sqrt{3}}{4}a^2[/tex]

Where, a is the side length.

Putting [tex]a=2[/tex], we get

[tex]A_1=\dfrac{\sqrt{3}}{4}(2)^2[/tex]

[tex]A_1=\dfrac{\sqrt{3}}{4}(4)[/tex]

[tex]A_1=\sqrt{3}[/tex]

[tex]A_1\approx \sqrt{3}[/tex]

The base and top of the prism are congruent so their area must be equal.

The lateral surface area of the prism is:

[tex]LA=Ph[/tex]

Where, P is the perimeter of the base and h is the height of the prism.

The lateral surface area of the prism is:

[tex]A_2=(2+2+2)5[/tex]

[tex]A_2=(6)5[/tex]

[tex]A_2=30[/tex]

Now, the total surface area is the sum of areas of bases and lateral surface area.

[tex]A=2A_1+A_2[/tex]

[tex]A=2(1.73)+30[/tex]

[tex]A=3.46+30[/tex]

[tex]A=33.46[/tex]

Therefore, the total surface area is 33.46 cm².

ACCESS MORE
EDU ACCESS