Answer: The answer is x=[tex]\frac{-3-\sqrt{65} }{4}[/tex], [tex]\frac{-3+\sqrt{65} }{4}[/tex]
Step-by-step explanation:
1) You can solve a situation like [tex]ax^2+bx+c=0[/tex] using the quadratic formula
[tex]x=-b[/tex]±[tex]\sqrt{b^2-4ac}[/tex] / 2a
2) Apply that to the problem and we get x= -3±[tex]\sqrt{3^2-4*2*(-7)}[/tex]/2*2
3) Solve what's inside the square root and what's at the denominator --> x=-3±[tex]\sqrt{65}[/tex]/4
4) separate the solutions ---> [tex]x=\frac{-3+\sqrt{65}}{4} , \frac{-3-\sqrt{65}}{4}[/tex]
5) Your final solutions are [tex]x=\frac{-3+\sqrt{65}}{4} , \frac{-3-\sqrt{65}}{4}[/tex]
