Question

One bag contains 6 red, 2 blue, and 3 yellow balls. A second bag contains 2 red, 4 blue, and 5 yellow balls. A third bag contains 3 red, 7 blue, and 1 yellow ball. One bag is selected at random. If 1 ball is drawn from the selected bag, what is the probability that the ball drawn is yellow?

Answer 1

Using it's concept, it is found that there is a 0.2727 = 27.27% probability that the ball drawn is yellow.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that the probabilities are as follows:

• 1/3 probability of picking the first bag, then 3/11 probability of picking a yellow ball.

• 1/3 probability of picking the second bag, then 5/11 probability of picking a yellow ball.

• 1/3 probability of picking the third bag, then 1/11 probability of picking a yellow ball.

Then, the probability of picking a yellow ball is given by:

$p = \frac{1}{3}\left(\frac{3}{11} + \frac{5}{11} + \frac{1}{11}\right) = \frac{9}{33} = 0.2727$

0.2727 = 27.27% probability that the ball drawn is yellow.

More can be learned about probabilities at https://brainly.com/question/24372153

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