Find the first two equations that are needed to solve the following story problem: How many milliliters of a 5% acid solution and how many milliliters of a 17% acid solution must be mixed to obtain 60 mL of a 13% acid solution? ​

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Answer:

Step-by-step explanation:

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.05x+.17y=.13

x+y=60

The two correct equations are "[tex]0.05 x+0.17 y=0.13[/tex] and [tex]x+y=60[/tex]". A further solution is provided below.

According to the question,

Let,

  • Quantity of 5% acid solution will be "x".
  • Quantity of 17% acid solution will be "y".

Given total acid solution,

= 60 mL

then,

→  [tex]x+y = 60[/tex]...(equation 1)

We know that the concentration of mixture = 13%

hence,

→  [tex]5 \ percent \ of \ x + 17 \ percent \ of \ y =13 \ percent (x+y)[/tex]

or,

→  [tex]0.05x+0.17y=0.13(60)[/tex]

Thus the above answer is correct.

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