Given: α is an angle in the second quadrant, csc α = 25/7; β is an angle in the first quadrant, cos β = √2/2. The value of tan ( α - β ) = _____.
-3/17
29/17
-31/17
15/17

Respuesta :

Answer:

-31/17

Step-by-step explanation:

csc²α-cot²α=1

cot²α=csc²α-1=(25/7)²-1=(625-49)/49=576/49

α is in 2nd quadrant so cotα is negative.

cot α=-√(576/49)=-24/7

tan α=-7/24

cos β=√2/2

sec β=2/√2=√2

sec²β-tan ²β=1

tan ²β=sec²β-1

tan²β=(√2)²-1=2-1=1

β is in 1st quadrant ,so tan β is positive.

tan β=1

[tex]tan (\alpha -\beta )=\frac{tan \alpha -tan \beta }{1+tan \alpha tan \beta } \\=\frac{\frac{-7}{24} -1}{1+(\frac{-7}{24}) (1)} \\=\frac{-7-24}{24-7} \\=\frac{-31}{17}[/tex]

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