Question

Suppose a basketball player is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single free throw). Assume that free throw shots are independent of one another. Find the probability that the player misses three consecutive free throws. 0.729 0.271 0.001 0.999

Answer 1

Answer:

The answer is "0.001 ".

Step-by-step explanation:

In this question, the shot value is missing So its solution can be defined a follows:

let

shot value= 3

The chances of missing a free takeoff $= 1- 0.90 = 0.1$

All three free throws are probably gone$= 0.1^3 = 0.001$