Question

Given f(x) = 3 and g(x) = cos(x). What is Limit of left-bracket f (x) minus g (x) right-bracket as x approaches negative pi?

2
3
4
DNE

Answer 1

Answer:

C

Step-by-step explanation:

cos pie= -1

so (3-(-1)=3+1=4

Answer 2

We apply limits concepts to solve this question. Since the functions have no discontinuity, we just replace the values, and 4 is the answer.

Functions:

The functions are:

$f(x) = 3$

$g(x) = \cos{x}$

Limit:

$\lim_{x \rightarrow -\pi} [f(x) - g(x)] = \lim_{x \rightarrow -\pi} [3 - \cos{x}] = 3 - \cos{\pi} = 3 - (-1) = 3 + 1 = 4$

Thus, 4 is the answer to this question.

For more on limits, you can check https://brainly.com/question/23145093