Answer:
Option A
Step-by-step explanation:
Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF
Area of ΔABH = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]
= [tex]\frac{1}{2}(6)(8-5)[/tex]
= 9 in²
Area of the trapezoid = [tex]\frac{1}{2}(CG+BH)(\text{Distance between these lines})[/tex]
= [tex]\frac{1}{2}(6+4)(5)[/tex]
= 25 in²
Area of ΔDEF = [tex]\frac{1}{2}(8)(6)[/tex]
= 24 in²
Therefore, area of the given figure = 9 + 25 + 24
= 58 in²
Option A will be the correct option.
