Question

a man who is red-green colorblind marries a woman with normal vision whose family has no history of colorblindness. which represents the probability their child being a female who is a carrier for blindness?

Answer 1

Answer:

50/50

Explanation:

Using a Punnett square, and using Rr to mean colorblindness, and rr as normal vision for genotypes, you can determine the probability of the child having colorblindness. R is the dominant gene, and r is the recessive one. So if you draw a square with 4 boxes, put R r on the top two, and r r on the side two, and fill in what the squares can be, you'll get 50/50 chances.