The length of AB = 5 units
What is the distance between points on a line parallel to X-axis?
"The distance between points [tex](x_1,y_1),(x_2,y_2)[/tex] on a line parallel to X-axis is, [tex]d=|x_2-x_1|[/tex] "
For given question,
From the graph of ΔABC,
The co-ordinates of A = (1, 2)
The co-ordinates of B = (6, 2)
For ΔABC, the side AB is parallel to X-axis.
Let [tex](x_1,y_1)=(1,2),(x_2,y_2)=(6,2)[/tex]
Using the formula for the distance between points on a line parallel to X-axis,
[tex]\Rightarrow d=|x_2-x_1|\\\\\Rightarrow d=|6-1|\\\\\Rightarrow d=|5|\\\\\Rightarrow d=5~units[/tex]
Therefore, the length of AB = 5 units
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