Given: QM is the angle bisector of ∠LMP QM is the angle bisector of ∠PQL Prove: LM ≅PQ
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Answer:
Step-by-step explanation:
QM is the angle bisector of ∠LMP
∠LMQ = ∠QMP
QM is the angle bisector of ∠PQL
∠PQM = ∠MQL
MQ = QM as common
By ASA, triangle MQP ≅ MQL
LM = PM and LQ = PQ as they are same side of congruent triangles
Triangle LPQ and LPM are isosceles
By angle bisector theorem, LP is perpendicular to MQ
By properties of rhombus, the two diagonals are perpendicular proves that LMPQ is a rhombus.
LM ≅ PQ
Answer:
Step-by-step explanation:
∠LMQ = ∠QMP QM is the angle bisector of ∠LMP
∠PQM = ∠MQL QM is the angle bisector of ∠PQL
MQ = QM common
MQP ≅ MQL ASA
LP ⊥ MQ angle bisector theorem
LMPQ is rhombus property of rhombus
LM ≅ PQ property of rhombus