Answer:
[tex]$2.63\times 10^{7} \ J$[/tex]
Explanation:
Given :
Total mass that a gondola can carry, m = 2250 kg
Displacement, s = 3345 - 2150
= 1195 m
Gravitational force, F = mg
= 2250 x 9.8
= 22050 N
Therefore the work done by the motor in moving the full gondola up the mountain,
W = F x s
= 22050 x 1195
= [tex]$2.63\times 10^{7}$[/tex] J