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18-05-2021
Mathematics

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A 37.5 mL solution contains 0.181 g of potassium chromate, K2CrO4 What is the
molarity?

A 375 mL solution contains 0181 g of potassium chromate K2CrO4 What is the molarity class=

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18-05-2021

Answer:

molarity=

194,19g/mol∗37.5mL

0.181g∗1000

=0,0248mol/L

Step-by-step explanation:

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