Question

The slope of the line containing the points (-5, 3) and (-2, 1) is
0 -2/3
O 2/3
-3/2

Answer 1

slope = (y2 - y1)/(x2 - x1) = (1 - 3)/(-2 - (-5)) = -2/(-2 + 5) = -2/3

For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3

A line passing through point (-4, 0) and parallel to the y-axis is x = -4

diameter=\sqrt{(7-1)^2+(5+3)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10diameter=

(7−1)

2

+(5+3)

2

=

6

2

+8

2

=

36+64

=

100

=10

radius = diameter/2 = 10/2 = 5

center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)

Required equation is (x - 1)^2 + (y - 4)^2 = 5^2

(x - 1)^2 + (y - 4)^2 = 25.

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