Please help me and show working. I have a test very soon.
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Answer:
good luck
Step-by-step explanation:
2/c-2 - 3/c+2=7/c^2 - 4
- and + is the same and x with % is the same so
2+2+4
c+c=c^2
2-3 but the 2 dont cont. it
4+3 it will be 7 soo
7/c^2-4
hope this helps u
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Answer:
c = 3
Step-by-step explanation:
Given
[tex]\frac{2}{c-2}[/tex] - [tex]\frac{3}{c+2}[/tex] = [tex]\frac{7}{c^2-4}[/tex] ← factor the difference of squares
[tex]\frac{2}{c-2}[/tex] - [tex]\frac{3}{c+2}[/tex] = [tex]\frac{7}{(c-2)(c+2)}[/tex]
Multiply through by (c - 2)(c + 2) to clear the fractions
2(c + 2) - 3(c - 2) = 7 ← distribute and simplify left side
2c + 4 - 3c + 6 = 7
- c + 10 = 7 ( subtract 10 from both sides )
- c = - 3 ( multiply both sides by - 1 )
c = 3