Question

Laura is bowling 5 games. Her first 4 scores were 103, 143, 101, and 110.
To end up with an average score of at least 126.8, what is the lowest score Laura will need in the fifth
game?

Answer 1

Answer:

The least 5th score is 177

Step-by-step explanation:

Given

$First\ 4: 103, 143, 101, 110.$

$Average = 126.8$

Required

The least 5th score

Represent the 5th score with x.

The average is calculated as:

$Average = \frac{\sum x}{n}$

So, we have:

$126.8 = \frac{103 + 143 + 101 + 110 + x}{5}$

$126.8 = \frac{457 + x}{5}$

Multiply both sides by 5

$634= 457 + x$

Solve for x

$x = 634- 457$

$x = 177$