Question

will give brainiest!
The Pythagorean Identity states that:
(sin x)2 + (cOS X)2 = 1
Given cos 0 = 6/10, find sin 0.
sin 0 = [ ? ] / [ ? ]
Simplify the fraction.

Answer 1

Answer:

$\frac{4}{5}$

Step-by-step explanation:

$( \cos \theta) ^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \therefore \: { \bigg( \frac{{6} }{10} \bigg)}^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \frac{36}{100} + ( \sin \theta) ^{2} = 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{64}{100} \\ \\ \sin \theta = \sqrt{\frac{64}{100} } \\ \\ \sin \theta = \frac{8}{10} \\ \\ \sin \theta = \frac{4}{5}$