Question

A flask contains 85.5 grams C12H2011 (sucrose) in 1.00 L of solution. What is the molarit
Your answer.
3.8 M
25 M
10M
1.2M

Answer 1

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

• Molar Mass of C₁₂H₂₂O₁₁ = (Molar Mass of C)*12 + (Molar Mass of H)*22 + (Molar Mass of O)*11

• Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol

• 85.5 g ÷ 342.3 g/mol = 0.25 mol

Then we divide the number of moles by the number of liters to calculate the molarity:

• 0.25 mol / 1.00 L = 0.25 M