Question

Linda performed the following trials in an experiment.
Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.
Trial 2: Heat 40.0 grams of water at 30.0 °C to a final temperature of 40.0 °C.
Which statement is true about the experiments? (5 points)
The heat absorbed in Trial 1 is about 1,674 ) greater than the heat absorbed in Trial 2.
O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2
O The same amount of heat is absorbed in both the experiments because the heat absorbed depends only on the final temperature,
The same amount of heat is absorbed in both the experiments because the product of mass, specific heat capacity, and change in temperature are the
same.

Answer 1

Answer:

O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water = 4.18J/g°C

∆T = change in temperature (°C)

* For trial 1:

m = 30g

∆T = 40°C - 0°C = 40°C

Q = 30 × 4.18 × 40

Q = 5016J

* For trial 2:

m = 40g

∆T = 40°C - 30°C = 10°C

Q = 40 × 4.18 × 10

Q = 1672J

From the above results, it is clear that the amount of heat absorbed in trial 1 (5016J) is greater than that absorbed in trial 2(1672J) with a difference of 3344.

Answer 2

Heat energy is generated by the movement of molecules, atoms, and ions. The heat absorbed in 1st trial is 3,347 greater than the heat absorbed in 2nd trial.

What is Specific heat?

Specific heat is given by the heat energy, mass of the substance, and the change in the temperature.

The heat transfer can be shown as,

$\rm Q = m \times c \times \Delta T$

Here, Q is the heat absorbed, m is mass, c is the specific heat, and delta T is the temperature change.

Q for trial 1:

$\begin{aligned} \rm Q& = \rm m \times c \times \Delta T\\\\&= 30 \times 4.18 \times 40\\\\&= 5016\;\rm J\end{aligned}$

Q for trial 2:

$\begin{aligned} \rm Q& = \rm m \times c \times \Delta T\\\\&= 40\times 4.18 \times 10\\\\&= 1672 \;\rm J\end{aligned}$

Therefore, in option B. the amount of heat absorbed in trial 1 is more than in trial 2.

Learn more about heat and energy here:

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