Use the given values of n and p to find the minimum usual value μ − 2σ and the
maximum usual value μ + 2σ. Round your answer to the nearest hundredth unless
otherwise noted.
n = 261, p =1/5
Minimum: 65.12; maximum: 39.28
Minimum: 39.28; maximum: 65.12
Minimum: 45.74; maximum: 58.66
Minimum: 43.06; maximum: 61.34
