Using the binomial distribution, it is found that the mean and the standard deviation of X are given as follows:
[tex]\mu_X = 3, \sigma_X = 0.87[/tex]
What is the binomial probability distribution?
The expected value of the binomial distribution is:
[tex]\mu_X = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sigma_X = \sqrt{np(1-p)}[/tex]
In this problem, the proportion and the sample size are given as follows:
Hence, the mean and the standard deviation are given by:
[tex]\mu_X = np = 4(0.75) = 3[/tex]
[tex]\sigma_X = \sqrt{np(1-p)} = \sqrt{4(0.75)(0.25)} = 0.87[/tex]
More can be learned about the binomial distribution at https://brainly.com/question/24863377
#SPJ2