Question

You have a mixture that contains 0.380 moles of Ne(g), 0.250 moles of He(g), and 0.500 moles CH4(g) at 400 K and 6.25 atm. What is the partial pressure of He?

Answer 1

Answer:

1.38 atm

Explanation:

Partial pressure of a gas = total pressure × mole fraction of that gas.

Mole fraction of a gas is moles of a gas ÷ total moles of all gases.

Answer 2

The partial pressure of Helium gas is 2.756 atm. This can be calculated by using mol fraction first.

Calculation of mol fraction:

It is the ratio of one mole of gas to the total moles of all the gases.

Total moles of all gases = 0.380+0.250+0.500 =1.13

Mol fraction of Helium gas = 0.500/1.13

Mol fraction of Helium gas = 0.442

Calculation of partial pressure:

It is the product of mol fraction of the gas to the total pressure given.

Partial pressure= 0.442 * 6.52 atm

Partial pressure=2.765 atm

Find more information about Mol fraction here:

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