Answer:
isosceles trapezoid
Step-by-step explanation:
1) find the distance of the points
[tex]\sqrt{(x2-x1)^2 + (y2 -y1)^2}[/tex]
AB = [tex]\sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}[/tex]
BC = |7-4| = 3
CD = [tex]\sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}[/tex]
AD = |9-2| = 7
2) equation of the line that passes threw BC
y = 7
3) equation of the line that passes threw AD
y = 5
conclusion
the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid
