Question

A pendulum is constructed by attaching a 4m rope to a bowling ball. It is then displaced 2m to one side and released.
Ignoring all effects of friction, and without knots,
a) Determine the period of the pendulum. Round to one decimal place.

Answer 1

Answer:

T = 4.0 s

Step-by-step explanation:

The period of a simple pendulum is given by

$period = 2\pi \sqrt{ \frac{l}{g} }$

where l = length of the pendulum

= 4 m

g = acceleration due to gravity

= 9.8 m/s^2

$period = 2\pi \sqrt{ \frac{(4 \: m)}{(9.8 \: \frac{m}{ {s}^{2} } )} } = 4.0 \: s$