Question

Currently, there are 1,460 wolves in Scataway National Park. If the population of wolves is growing at a rate of 6% every year,
which function represents the number of wolves in Scataway National Park in tyears?
OA W0 = 1,460(1.06)
B. WO = 1,460(0.94)
OC M6 = 1,460(0.06)
OD. WO = (1,460)(1.06)

Answer 1

Answer:

$P(t) = 1460(1.06)^t$

Step-by-step explanation:

Exponential equation for population growth:

The exponential equation for a population after t years is given by:

$P(t) = P(0)(1+r)^t$

In which P(0) is the initial population and r is the growth rate, as a decimal.

Currently, there are 1,460 wolves in Scataway National Park.

This means that $P(0) = 1460$

Growing at a rate of 6% every year:

This means that $r = 0.06$. So

$P(t) = P(0)(1+r)^t$

$P(t) = 1460(1+0.06)^t$

$P(t) = 1460(1.06)^t$

Answer 2

Answer:

Step-by-step explanation: