Answer:
[tex]Mid(A) = 73[/tex]
[tex]IQR(B) = 8[/tex]
The difference of the medians of class A and class B is between the interquartile range of either data set.
Step-by-step explanation:
Given
The attached box plots
To answer this, see attached image for how to read a box plot
With reference to the attached image of how to read the box plot;
Solving (a): The median of class A
[tex]Mid(A) = 73[/tex]
Solving (b): IQR of class B
IQR is calculated as:
[tex]IQR =Q_3 - Q_1[/tex]
From the box plot of class B, we have:
[tex]Q_3 = 87[/tex]
[tex]Q_1 = 79[/tex]
So, we have:
[tex]IQR(B) = 87 - 79[/tex]
[tex]IQR(B) = 8[/tex]
Solving (c):
[tex]Mid(A) = 73[/tex]
[tex]Mid(B) = 82[/tex]
[tex]IQR(B) = 8[/tex]
IQR of class A is calculated as:
[tex]IQR =Q_3 - Q_1[/tex]
From the box plot of class A, we have:
[tex]Q_3 = 76[/tex]
[tex]Q_1 = 68[/tex]
So, we have:
[tex]IQR(A) = 78 - 68[/tex]
[tex]IQR(A) = 10[/tex]
The difference (d) between the medians is:
[tex]d =Mid(B) - Mid(A)[/tex]
[tex]d = 82 - 73[/tex]
[tex]d = 9[/tex]
From [tex]smallest[/tex] to [tex]largest[/tex], we have: 8, 9, 10
i.e. IQR(B), d, IQR(A)