A power company calculates a person's monthly bill from the number of kilowatt-hours (kWh), x, used. The function b(x) = { 0.150, s 0.10 (x – 200) + 30, x < 200 2 > 200 determines the bill. How much is the bill for a person who uses 300 kWh in a month? O A. $60 O B. $55 C. $40 D. $45​

Respuesta :

The bill for a person who uses 300 kWh in a month is $40

How to determine the bill of the person?

The piecewise function of how the power company calculates the bill is given as:

b(x) = 0.150x, x < 200

b(x) = 0.10(x - 200) + 30, x >= 200

For a person who uses 300 kWh in a month, the value of x is 300.

i.e. x = 300

By comparing the domain of the piecewise function, we make use of the following function

b(x) = 0.10(x - 200) + 30, x >= 200

Remove the domain

b(x) = 0.10(x - 200) + 30

Substitute the known values in the above equation

b(300) = 0.10(300 - 200) + 30

Evaluate the difference

b(300) = 0.10(100) + 30

Evaluate the product

b(300) = 10 + 30

Evaluate the sum

b(300) = 40

Hence, the bill for a person who uses 300 kWh in a month is $40


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