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  • 17-05-2021
  • Mathematics
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Can someone help me with this please?

Can someone help me with this please class=

Respuesta :

msm555
msm555 msm555
  • 17-05-2021

Answer:

Solution given:

<J=90°[tangent to the circle is perpendicular to radius]

In right angled triangle ∆KJL

base[b]=10

hypotenuse [h]=x+10

perpendicular [p]=24

by using Pythagoras law

p²+b²=h²

24²+10²=(x+10)²

(x+10)²=676

x+10=√676

x=26-10

x=16

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