Question

The square based pyramid whose length of side of square base and slant height are in the ratio 6:5 and volume is 48000cm^3 .Find the total surface area

Answer 1

Answer:

$A=9600cn^2$

Step-by-step explanation:

From the question we are told that:

Ratio of square base and slant height $R=6:5$

Volume $V=48000cm^3$

Generally the equation for height  Pyramid h is mathematically given by

  $h^2=s^2+(\frac{1}{2}a^2)$

  $h=\sqrt{s^2+(\frac{1}{2}a)^2)}$

  $h=\sqrt{5^2+3^2}$

  $h=4$

   Where

    a= base Length

    s=slant height of pyramid

Therefore the ratio of height is

  $h=4$

Generally the equation for The Volume of  Square  based Pyramid V is mathematically given by

 $V=a^2\frac{h}{3}$

 $V=6^2\frac{4}{3}$

 $V=48$

Therefore the ratio of volume is

 V=48

Generally for V=4800

Therefore

  $a=60$

  $h=40$

Generally the equation for Area of Square  based Pyramid A is mathematically given by

  $A=a^2+2a\sqrt{\frac{a^2}{4}+h^2 }$

 $A=60^2+2(60)\sqrt{\frac{(60)^2}{4}+(40)^2}$

 $A=9600cn^2$

Therefore the Area of Square  based Pyramid A is

 $A=9600cn^2$