Respuesta :

Answer:

120 combinations of CDs are possible

Step-by-step explanation:

The total combinations could be

[tex]10C_3[/tex]

[tex]\frac{10*9*8*7!}{7!*3!}[/tex]

On further expanding, we get -

[tex]\frac{10*9*8}{3!} \\\frac{10*9*8}{3*2*1} \\= 10*3*4\\= 120[/tex]

Hence, 120 combinations of CDs are possible

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