Question

At 304 K, a 9.6 L tank contains 1.9 moles of H2 gas under an unknown pressure in atm. What is the pressure of the gas in the tank? (R = 0.0821 L*atm/mol*K)

Answer 1

Answer:

The pressure is 4.939 atm

Explanation:

As we know

PV = nRT

where P is the pressure

V is the volume

n is the total number of moles

R is the gas constant

and T is the temperature

Substituting the given values we get -

$P * 9.6 = 1.9 * 0.0821 *304\\P = 47.420/9.6\\P = 4.939$

The pressure is 4.939 atm

Answer 2

Answer:

4.9 atm

Explanation: