Question

A certain television is advertised as a 83-inch TV (the diagonal length). If the height of the TV is 45 inches, how wide is the TV? Round to the nearest tenth of an inch.

Answer 1

Answer: 69.7 inch

Step-by-step explanation:

Given

A television is advertised as 83 inch TV(diagonal length)

The height of the TV is 45 inches

Suppose, width is x

Using Pythagoras theorem, we can write

$\Rightarrow 83^2=45^2+x^2\\\Rightarrow x^2=83^2-45^2\\\Rightarrow x^2=6889-2025\\\Rightarrow x=69.7\ \text{inch}$