A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. A child randomly pulls 4 marbles from the bag. What is the probability that the marbles chosen are green, blue, red, and yellow? Round your answer to the nearest hundredth.

A bag contains 7 marbles one each of red orange yellow green blue violet and white A child randomly pulls 4 marbles from the bag What is the probability that th class=

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Answer:

Probability of getting green, blue, red, and yellow = 0.69

Step-by-step explanation:

Given - A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. A child randomly pulls 4 marbles from the bag.

To find - What is the probability that the marbles chosen are green, blue, red, and yellow?

Proof -

Given that,

A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white.

i.e.

All the outcomes are equally likely.

So,

The child can choose the 4 marbles in 4! ways.

And

Total number of ways = [tex]^{7} C_{4}[/tex] = 35

So,

Probability of getting green, blue, red, and yellow = [tex]\frac{4!}{35}[/tex]

                                                                                   = [tex]\frac{24}{35}[/tex] = 0.69

Probability of getting green, blue, red, and yellow = 0.69

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