Question

A spinner has 8 equal-sized sections. Four of the sections are blue, two are red, and two are green. The pointer lands in a red section 8 times in 20 spins. How does this compare to the number of times the pointer is expected to land in a red section?

Answer 1

Answer:

The experimental outcome is greater than the expected outcome

Step-by-step explanation:

Given

$n = 8$ --- sections

$Blue = 4$

$Red = 2$

$Green = 2$

$Red = 8\ in\ 20$ ---- outcome of the experiment

First, we calculate the theoretical probability of Red

$P(Red) = \frac{Red}{n}$

$P(Red) = \frac{2}{8}$

$P(Red) = 0.25$

So, in 20 rolls; The expected outcome of Red is:

$Expected = 20 * 0.25$

$Expected = 5$

Given that the experiment produces Red 8 times in 20 spins.

We can conclude that the experimental outcome is greater than the expected outcome