Respuesta :

Answer:

(a) 1, 2, 3, 6, 8

Step-by-step explanation:

Given

[tex]Median = 3[/tex]

[tex]Mean = 4[/tex]

Required

The sequence of hours worked each day

See attachment for options

From the question, we understand that:

[tex]Median = 3[/tex]

This means that, the middle number is 3 (when sorted)

So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively

Next, is to determine the mean of (a) and (d)

The mean of a data is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

(a)

[tex]\bar x = \frac{1+ 2+ 3+ 6+ 8}{5}[/tex]

[tex]\bar x = \frac{20}{5}[/tex]

[tex]\bar x = 4[/tex]

(d)

[tex]\bar x = \frac{1+ 2+ 3+ 4+ 5}{5}[/tex]

[tex]\bar x = \frac{15}{5}[/tex]

[tex]\bar x = 3[/tex]

Option (a) is true, because it has:

[tex]Median = 3[/tex]

[tex]Mean = 4[/tex]

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