Answer:
(a) 1, 2, 3, 6, 8
Step-by-step explanation:
Given
[tex]Median = 3[/tex]
[tex]Mean = 4[/tex]
Required
The sequence of hours worked each day
See attachment for options
From the question, we understand that:
[tex]Median = 3[/tex]
This means that, the middle number is 3 (when sorted)
So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively
Next, is to determine the mean of (a) and (d)
The mean of a data is calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
(a)
[tex]\bar x = \frac{1+ 2+ 3+ 6+ 8}{5}[/tex]
[tex]\bar x = \frac{20}{5}[/tex]
[tex]\bar x = 4[/tex]
(d)
[tex]\bar x = \frac{1+ 2+ 3+ 4+ 5}{5}[/tex]
[tex]\bar x = \frac{15}{5}[/tex]
[tex]\bar x = 3[/tex]
Option (a) is true, because it has:
[tex]Median = 3[/tex]
[tex]Mean = 4[/tex]