Respuesta :
Answer:
T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)
Step-by-step explanation:
We know MH+MH+MH=TM
MH is a two digit number, and TM is also a two digit number.
MH+MH+MH=3*(MH)<100
3M<=9, meaning that M could be 1, 2, or 3.
If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1
30+3H=10T+1, so 3H must include 1 in one's digit.
The only possibility is that 3H = 21, then H = 7
MH+MH+MH=17+17+17=TM=51, T = 5
If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2
60+3H=10T+2, so 3H must include 2 in one's digit.
The only possibility is 3H = 12, then H = 4
MH+MH+MH=24+24+24=72, T = 7
If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3
90+3H=10T+3, so 3H must include 3 in one's digit.
The only possibility is 3H = 3, then H =1
MH+MH+MH=31+31+31=93, T=9
We will see that if we define M = 2, and H = 4, the value that T takes is T = 7
Which digit the letter T represent?
We know that:
MH + MH + MH = TM
We can write this as:
M*10 + H + M*10 + H + M*10 + H = T*10 + M
30*M + 3*H = T*10 + M
30*M - M + 3*H = T*10
(29*M + 3*H)/10 = T
Now we need to find two values for M and H such that T is a digit.
For example, if M = 2 we have:
(29*2 + 3*H)/10 = T
(58 + 3*H)/10 = T
Now we can take H = 4, then we get:
(58 + 3*4)/10 = T
(58 + 12)/10 = T = 7
In this case, we found that a possible value of T is T = 7.
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